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永恒狂刀最新验证码

时间:2015-9-28 15:02:19   作者:狂刀-追逐   来源:永恒狂刀官网   阅读:3254   评论:0
内容摘要:      今天给永恒狂刀会员出来特殊福利。此次验证很难的技术花3天时间技术破解这个最新的验证:看图操作: 使用物品("回收宝箱(永久)")等待(2000)aa=NPC对话内容aa=string.gsub(aa,"0","0")aa=string.gsub(aa,"1","1")...
      今天给永恒狂刀会员出来特殊福利。此次验证很难的技术花3天时间技术破解这个最新的验证:看图操作:
永恒狂刀最新验证码

 使用物品("回收宝箱(永久)")
等待(2000)
aa=NPC对话内容
aa=string.gsub(aa,"0","0")
aa=string.gsub(aa,"1","1")
aa=string.gsub(aa,"2","2")
aa=string.gsub(aa,"3","3")
aa=string.gsub(aa,"4","4")
aa=string.gsub(aa,"5","5")
aa=string.gsub(aa,"6","6")
aa=string.gsub(aa,"7","7")
aa=string.gsub(aa,"8","8")
aa=string.gsub(aa,"9","9")

aa=string.gsub(aa,"0","0")
aa=string.gsub(aa,"①","1")
aa=string.gsub(aa,"②","2")
aa=string.gsub(aa,"③","3")
aa=string.gsub(aa,"④","4")
aa=string.gsub(aa,"⑤","5")
aa=string.gsub(aa,"⑥","6")
aa=string.gsub(aa,"⑦","7")
aa=string.gsub(aa,"⑧","8")
aa=string.gsub(aa,"⑨","9")

aa=string.gsub(aa,"0","0")
aa=string.gsub(aa,"⑴","1")
aa=string.gsub(aa,"⑵","2")
aa=string.gsub(aa,"⑶","3")
aa=string.gsub(aa,"⑷","4")
aa=string.gsub(aa,"⑸","5")
aa=string.gsub(aa,"⑹","6")
aa=string.gsub(aa,"⑺","7")
aa=string.gsub(aa,"⑻","8")
aa=string.gsub(aa,"⑼","9")

pass1=匹配内容(aa,[[(面\d个)]])
--输出信息(pass1)
if pass1~=nil then
   pp=匹配内容(pass1,[[(\d)]])
   --输出信息(pp)
end

passcode=""
for i=1,15 do
k1=匹配内容(aa,[[(\d/SCOLOR=253)]])
  if k1~=nil then
    k2=匹配内容(k1,[[(\d)]])
    aa=string.gsub(aa,k1,"",1)
     if k2~=nil then
     passcode=table.concat{passcode,k2}

     end

  end

end

passcode=string.sub(passcode,1,pp)
输出信息(passcode)
if passcode~=nil then
findapi=匹配内容(NPC对话内容,[[(@@inputstring\d{1,3})]]) 
if findapi~=nil then 
api=findapi   
else  
api=匹配内容(NPC对话内容,[[(@@inputstring\d{1,3})]])
end     
合成命令(api,passcode) 
end



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